Question

X² +10x+3=0

how do I slove it with the quadratic formula?​

Answer 1

Explanation:

Answer 2

The equation is already in standard form [ ax² + bx + c = y ] so we can find the values of each variable.

a = 1

b = 10

c = 3

y = 0

Quadratic formula:
`x = (-b+-√(b^2-4ac) )/(2a)`

Solve using the formula:

`x=(-10+-√(10^2-4(1)(3)) )/(2(1))`

`x=(-10+-√(100 - 12) )/(2)`

`x=(-10+-√(88) )/(2)`

`x=-5+-√(22)`

Therefore, the answer is [ x = -5 ± √22 ]

Best of Luck!