Question

I dont know how to do this, i mean i do but its hard

Answer 1

Explanation:

opposite= 8 : the length opposite angle c

adjacent=15 : the length next to angle c, not the hypotenuse

hypotenuse= 17 : the hypotenuse will always be opposite the right angle

`sinC=(opposite)/(hypotenuse)\\ \\sinC=(8)/(17)`

`cosC=(adjacent)/(hypotenuse)\\\\cosC=(15)/(17)`

`tanC=(opposite)/(adjacent) \\\\tanC=(8)/(15)`