Question

The equation represents the combustion of sucrose. C12H22O11 + 12O2 Right arrow. 12CO2 + 11H2O If there are 10.0 g of sucrose and 8.0 g of oxygen, how many moles of sucrose are available for this reaction? 0.029 mol 0.250 mol 0.351 mol 3.00 mol

Answer 1

A

Step-by-step explanation:

Answer 2

Answer: 0.029 mol

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

The balanced chemical equation is:

`C_(12)H_(22)O_(11)+12O_2\rightarrow 12CO_2+11H_2O`

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=(10.0g)/(342g/mol)}=0.029moles`

Thus there are 0.029 moles of sucrose