Question

Solve for x
3 x − 8 ≤ 23 AND − 4 x + 26 ≥ 6
Please help thank you!!

Answer 1

To solve for x, you need to isolate/get the variable "x" by itself in the inequality:

3x - 8 ≤ 23 Add 8 on both sides

3x - 8 + 8 ≤ 23 + 8

3x ≤ 31 Divide 3 on both sides to get "x" by itself

`(3x)/(3) \leq (31)/(3)`

`x\leq (31)/(3)` (x is any number less than or equal to 31/3)

-4x + 26 ≥ 6 Subtract 26 on both sides

-4x ≥ -20 Divide -4 on both sides [When you multiply/divide by a negative number to both sides of an inequality, you flip the sign </>]

`(-4x)/(-4) \geq (-20)/(-4)` (two negative signs cancel each other out and become positive)

x ≤ 5 (x is any number less than or equal to 5)