Question

X is a normally distributed random variable with a mean of 8 and a standard deviation of 4. The probability that x is between 1. 48 and 15. 56 is.

Answer 1

P(1.48<X<15.56) ≈ 0.919 ≈ 91.9%

Explanation:

2nd+DISTR --> normalcdf

P(1.48<X<15.56) = normalcdf(1.48,15.56,8,4) ≈ 0.919