Question

A Young's interference experiment is performed with blue-green laser light. The separation between the slits is 0.500 mm, and the screen is located 3.24 m from the slits. The first bright fringe is located 3.22 mm from the center of the interference pattern. What is the wavelength of the laser light?

Answer 1

λ = 4.97 x 10⁻⁷ m = 497 nm

Step-by-step explanation:

The formula for the distance of a bright fringe from center in Young's double slit experiment, is given by:

y = mλL/d

where,

y = distance of bright fring from center = 3.22 mm = 3.22 x 10⁻³ m

m = No. of bright fringe = 1

L = Distance between slits and screen = 3.24 m

d = slit separation = 0.5 mm = 0.5 x 10⁻³ m

λ = wavelength of light = ?

3.22 x 10⁻³ m = (1)(λ)(3.24 m)/(0.5 x 10⁻³ m)

(3.22 x 10⁻³ m)(0.5 x 10⁻³ m)/(3.24 m) = λ

λ = 4.97 x 10⁻⁷ m = 497 nm