Question

What is the theoretical yield of sodium chloride for the reaction of 55.0 g of Na

D
with 67.2 g Cl2?
g
a. 1.40 x 102 g NaCl
b. 111 g NaCl
c. 55.4 g NaCl
222 g NaCl

Answer 1

Its B hope it helps:))

Answer 2

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Actually Welcome to the concept of Physical chemistry, and Stochiometry.

So we balance the equation as,

2Na + Cl2 ===> 2NaCl

The required reaction is as:

2Na+ Cl2 = 2NaCl

2 moles Na = 2×23 g = 46g,1 mole Cl2 = 2×35.5g=71g

Now,71g Cl2 reacts with 46g Na,

Therefore, 67.2g Cl2 reacts with 46×67.2/71= 43.54g Name

The rest Na = (55–43.54)g=11.46g

That means Cl2 is a limiting reactant.

Again,2 moles NaCl=2(23+35.5)g=117g

Then,71g Cl2 produce 117g NaCl

Therefore,67.2g Cl2 produce 117×67.2/71 = 110.74g NaCl

hence the correct option is, b.) 111 g NaCl