Question

In the past, many students have listed that the accidental addition of too much acetic acid contributed greatly to the difference between the experimental value and the accepted value. Suppose that Student A was supposed to make a 0.18 M solution by diluting 9.0 mL of 2.0 Macetic acid to 100.0 mL. The expected pH for this solution is 2.74. The K of acetic acid is 1.8 x 10

a. What would be the expected pH if a Student A accidentally diluted 9.1 mL (instead of 9.0 mL) of the acid to 100 mL?

b. If student A measured the above calculated pH, what would be the resultant K of acetic acid given that they expected the acid to have an initial concentration of 0.18M.

Answer 1

a. What would be the expected pH if a Student A accidentally diluted 9.1 mL (instead of 9.0 mL) of the acid to 100 mL? = 2.7423

b. If student A measured the above calculated pH, what would be the resultant K of acetic acid given that they expected the acid to have an initial concentration of 0.18M. = 1.838 x 10 ∧-5

Step-by-step explanation:

check the attached file for explanation.