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In traveling to the Moon, astronauts aboard the Apollo spacecraft put themselves into a slow rotation to distribute the Sun's energy evenly. At the start of their trip, they accelerated from no rotation to 1.0 revolution every minute during a 12-min time interval. The spacecraft can be thought of as a cylinder with a diameter of 8.3 m .

1) Determine the angular acceleration of a point on the skin of the ship 2.5 min after it started this acceleration.

2) Determine the radial component of the linear acceleration of a point on the skin of the ship 2.5 min after it started this acceleration.

3) Determine the tangential component of the linear acceleration of a point on the skin of the ship 2.5 min after it started this acceleration.

User Abhinav
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Answer:

1)
\alpha \approx 8.727* 10^(-3)\,(rad)/(s^(2)), 2)
a_(r) = 14.222\,(m)/(s^(2)), 3)
a_(t) = 0.072\,(m)/(s^(2))

Step-by-step explanation:

1) Let consider that Apollo spacecraft accelerates at constant rate. The angular acceleration of the spacecraft is:


\alpha = \left((1\,(rev)/(min) )/(12\,min)\right)\cdot \left((2\pi\,rad)/(1\,rev) \right)\cdot \left((1\,min)/(60\,s) \right)


\alpha \approx 8.727* 10^(-3)\,(rad)/(s^(2))

2) The angular speed of the Apollo spacecraft at t = 2.5 min is:


\omega = \left(8.727* 10^(-3)\,(rad)/(s^(2)) \right)\cdot (150\,s)


\omega = 1.309\,(rad)/(s)

The radial component of the linear acceleration is:


a_(r) = \left(1.309\,(rad)/(s)\right)^(2)\cdot (8.3\,m)


a_(r) = 14.222\,(m)/(s^(2))

3) The tangential component of the linear acceleration is


a_(t) = \left(8.727* 10^(-3)\,(rad)/(s)\right)\cdot (8.3\,m)


a_(t) = 0.072\,(m)/(s^(2))

User Skotnik
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