Answer:
Normal distribution
Explanation:
From the statement we have the following information:
Average sample, m = $ 3120
Sample size, n = 40
Population standard deviation, sd = $ 677
Because we know the standard deviation of the population and that in addition the sample size is also greater than 30 (is 40) we can say that the distribution of university earnings is a normal distribution, that is, we can use the z test to build a confidence interval