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Solve: 18^x^2+4x+4 = 18^9x+18

User Deadron
by
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2 Answers

5 votes

Answer:

c

Explanation:

got it right on edge

User Skibee
by
8.1k points
5 votes

Answer:

x = -2 or +7

Explanation:

We presume you want to solve ...

18^(x^2 +4x +4) = 18^(9x +18)

Equate exponents of the same base and put the quadratic in standard form.

x^2 +4x +4 = 9x +18

x^2 -5x -14 = 0

(x -7)(x +2) = 0

Values of x that make these factors zero are 7 and -2.

The solutions are x=-2 or x = 7.

User Rluba
by
7.8k points

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