Question

Find the area of the plane figure :​

Answer 1

99.9
`cm^(2)`

Explanation:

Given, AB=13 cm, BC=4 cm

AC is the diagonal of parallelogram ABCD.

Also AC=16 cm

We know, △ABC≅△ACD [S−S−S Congruence]

Also, area of parallelogram ABCD = Area of △ABC + Area of △ACD

= 2 × Area of △ABC

=
`2√(s(s-13)(s-4)(s-15))`

`s= (13+15+4)/(2)` =
`2√(16(16-13)(16-4)(16-15))`

= 16 = 99.9