Question

The length of a basketball court is twice its

width. The perimeter is 150 feet. Find the
length and width of the basketball court.

Answer 1

The width of the basketball court is 25 feet and the length is 50 feet.

Step-by-step explanation:

Let's assume the width of the basketball court is 'x' feet. Since the length is twice the width, we can say the length is '2x' feet.

The perimeter of a rectangle is calculated by adding all of its sides. So, in this case, we have 2 lengths and 2 widths.

Perimeter = 2(length) + 2(width)

Given that the perimeter is 150 feet, we can write the equation: 150 = 2(2x) + 2(x)

Simplifying the equation, we get: 150 = 6x

Dividing both sides by 6, we find: x = 25

Therefore, the width of the basketball court is 25 feet and the length is 2x, which is 2 * 25 = 50 feet.

Answer 2

Given:

The length of a basketball court is twice its width.

The perimeter of the perimeter is 150 feet.

To find the length and width of the basketball court.

Formula

The perimeter of the rectangle is

`P = 2(l+b)`

where, l be the length of the rectangle and

b be the width of the rectangle.

Now,

As per the problem,

Let, the width be
`x`, so the length be
`2x`

So,

The perimeter is =
`2(x+2x) = 6x`

According to the problem,

`6x = 150\\or, x = (150)/(6)`

`or, x = 25`

Therefore,

the width of the court is 25 ft and length = 2×25 = 50 ft

Hence,

The length and width of the basketball court is 50 ft and 25 ft respectively.