Question

Find the magnitude of the magnetic flux through the floor of a house that measures 25 m by 15 m . Assume that the Earth's magnetic field at the location of the house has a horizontal component of 3.0×10−5 T pointing north, and a downward vertical component of 3.9×10−5 T .

Answer 1

0.0185 Wb

Step-by-step explanation:

The magnitude of the magnetic flux through the floor of the house is given as:

|Φ| = |B| * A

Where B is the magnetic field through the floor and A is the area of the floor.

Magnetic field, B, is a vector and it is given as:

B = (3.0 * 10^(-5)) i + (3.9 * 10^(-5)) j

We have to first find the magnitude of the Magnetic field, |B|:

|B| = √{[3.0 * 10^(-5)]^2 + [3.9 * 10^(-5)^2]}

|B| = 4.92 * 10^(-5) T

The area of the floor is:

A = 25 * 15 = 375 m²

Therefore:

|Φ| = 4.92 * 10^(-5) * 375

|Φ| = 0.0185 Wb

The magnitude of the Magnetic Flux is 0.0185 Wb.