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How many grams of propane (c3h8) are required to produce 39.4g of water

How many grams of propane (c3h8) are required to produce 39.4g of water
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How many grams of propane (c3h8) are required to produce 39.4g of water

User MarekLi
by
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1 Answer

4 votes

Answer:

96.12 grams

Step-by-step explanation:

C3H8 + H2O

Mass 96.12 39.4

RFM 44 18

Moles 2.19 2.19

User NagarjunaReddy
by
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