Question

You fill a vertical glass tube to a depth of 15.0 cm with freshwater. You then pour on top of the water an additional 15.0 cm of gasoline (density 7.40×102kg/m3), which does not mix with water. The upper surface of the gasoline is exposed to the air. Find the gauge pressure at the interface between the gasoline and water.

Answer 1

1087.8 Pa

Step-by-step explanation:

given that:

You fill a vertical glass tube to a depth of 15.0 cm with freshwater.

i.e Height (h₁) of the tube = 15.0 cm =0.15 m

Additional 15.0 cm of gasoline was added = 0.15 m

the density of the gasoline
`\rho_g` = 7.40×10² kg/m³ = 740 kg/m³

acceleration due to gravity (g) = 9.8 g

the gauge pressure at the interface between the gasoline and water can be determined as =
`\rho_g g h`

= 740 × 9.8 × 0.15

= 1087.8 Pa

Thus, the gauge pressure at the interface between the gasoline and water = 1087.8 Pa