Question

A centrifuge in a forensics laboratory rotates at an angular speed of 3,700 rev/min. When switched off, it rotates 46.0 times before coming to rest. Find the constant angular acceleration of the centrifuge (in rad/s2). Consider the direction of the initial angular velocity to be the positive direction, and include the appropriate sign in your result.

Answer 1

Step-by-step explanation:

Given,

initial angular speed, ω = 3,700 rev/min

=
`3700* (2\pi)/(60)=387.27\ rad/s`

final angular speed = 0 rad/s

Number of time it rotates= 46 times

angular displacement, θ = 2π x 46 = 92 π

Angular acceleration

`\alpha = (\omega_f^2 - \omega^2)/(2\theta)`

`\alpha = (0 - 387.27^2)/(2* 92\ pi)`

`\alpha = -259.28 rad/s^2`