The equation of a circle whose center is at (4,0) and radius is length 2 (3) is (x - 4)2 + y2 = 213 (X - 4)2 + y2 = 12 (x + 4)2 + y2 = 12

asked Aug 17, 2021 230k views

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The equation of a circle whose center is at (4,0) and radius is length 2 (3) is

(x - 4)2 + y2 = 213
(X - 4)2 + y2 = 12
(x + 4)2 + y2 = 12

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2 votes

Answer:

I think the answer is (x-4)2 + y2 = 12 :) sorry if i am wrong***

Explanation:

TonyParker answered Aug 21, 2021

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