Question

1. What is the temperature in °C if 1.32 moles of a gas that occupies.35 L at a

pressure of 1.06 atm?

Answer 1

-269.65 °C is the temperature in °C if 1.32 moles of a gas that occupies.35 L at a pressure of 1.06 atm.

Step-by-step explanation:

Data given:

number of moles of the gas, n = 1.32

volume of the gas, V = 0.35 litres

pressure of the gas, P = 1.06 atm

temperature, T =?

R (gas constant) = 0.0821 L atm/mole K

Applying the equation for the ideal gas law:

PV = nRT

rearranging the equation:

T =
`(PV)/(nR)`

putting the values in the equation:

T =
`(0.35 X 1.06 )/(0.0821 X 1.32)`

T = 3.5 K

since the unit of temperature obtained is in degrees the temperature in Kelvin is -269.65 degrees. As 0 Kelvin = -273.15 celsius

formula is K -273.15

So,

3.5 - 273.15

= -269.65 celsius