Answer:
The value of the test statistics is 1.85.
Explanation:
We are given that a political study took a sample of 900 voters in the town and found that 62% of the residents favored construction.
Using the data, a political strategist wants to test the claim that the percentage of residents who favor construction is above 59%.
Let p = percentage of residents who favor construction.
SO, Null Hypothesis,
: p
59% {means that the percentage of residents who favor construction is below or equal to 59%}
Alternate Hypothesis,
: p > 59% {means that the percentage of residents who favor construction is above 59%}
The test statistics that will be used here is One-sample z proportion statistics;
T.S. =
~ N(0,1)
where,
= percentage of residents who favor construction in a sample of 900 voters = 62%
n = sample of voters = 900
So, test statistics =
![\frac{0.62-0.59}{{\sqrt{(0.62(1-0.62))/(900) } } } }](https://img.qammunity.org/2021/formulas/mathematics/college/bptq5tjy7fj8grfv5jlmbzpojk3ax8p2z9.png)
= 1.85
The value of the test statistics is 1.85.