Answer:
d) A two-sample z-interval for a difference in sample proportions
Explanation:
Explanation:-
Given data a random sample of 40 engines of one design, 14 failed to ignite as a result of fuel system error.
First sample proportion
![p_(1) = (14)/(40) = 0.35](https://img.qammunity.org/2021/formulas/mathematics/college/l611tnv9ji2nc3dualj7dpy2dfmefgarca.png)
Given data random sample of 30 engines of a second design, 9 failed to ignite as a result of fuel system error.
second sample proportion
![p_(2) = (9)/(30) = 0.30](https://img.qammunity.org/2021/formulas/mathematics/college/90xe8ixpkivlaild9tqof2mtwyb5r9vxvl.png)
Null hypothesis: H₀: Assume that there is no significant between the two designs
H₀: p₁ = p₂
Alternative Hypothesis: H₁:
H₁: p₁ ≠ p₂
The test statistic
![Z = \frac{p_(1)-p_(2) }{\sqrt{p q((1)/(n_(1) ) + (1)/(n_(2) ) } )}](https://img.qammunity.org/2021/formulas/mathematics/college/vgc628i72645fz18zipege5vhao8eztvcx.png)
where
![p = (n_(1) p_(1)+n_(2) p_(2) )/(n_(1) +n_(2) )](https://img.qammunity.org/2021/formulas/mathematics/college/8x6dankzpv5oo1o3f5zm9q0o0rrl61cwng.png)
q =1-p