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Relative to the circle with the equation x^2 + y^2 = 4 how has the circle with the equation (x+5)^2 + (y-6)^2 = 4 been shifted, what is the radius of the circle

Relative to the circle with the equation x^2 + y^2 = 4 how has the circle with the equation (x+5)^2 + (y-6)^2 = 4 been shifted, what is the radius of the circle
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Relative to the circle with the equation x^2 + y^2 = 4 how has the circle with the equation (x+5)^2 + (y-6)^2 = 4 been shifted, what is the radius of the circle

User Jackson Ming Hu
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1 Answer

4 votes

Answer:

the circle is shifted -5 on the x and +6 on the y. Center is (-5,6). Radius = 2.

Explanation:

User Goofyahead
by
8.2k points
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