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10 votes
10 votes
Which fraction represents the decimal 0.8888...?

StartFraction 80 Over 99 EndFraction
StartFraction 1,111 Over 1,250 EndFraction
Eight-ninths
Nine-eighths

User Doub
by
2.7k points

2 Answers

22 votes
22 votes


\begin{gathered}\begin{gathered}\boxed{\begin{array}{}\sf { \rightarrow \: \red{i \: dont \: know \: anymore}}\end{array}}\end{gathered} \end{gathered}
\begin{gathered}\begin{gathered}\boxed{\begin{array}{}\sf { \rightarrow \: \red{i \: dont \: know \: anymore\:\color{green}☘}}\end{array}}\end{gathered} \end{gathered}


\color {blue} \rule {1pt} {100000pt}

User StevenDStanton
by
2.8k points
10 votes
10 votes

Answer:

8/9

Explanation:

A fraction that has denominator factors of 2 or 5 (only) will be finite in length. It will not be a repeating decimal fraction. This eliminates choices B and D.

The number of 9s in the denominator of a repeating decimal fraction will be equal to the number of repeating digits. The fraction 0.8888... has one repeating digit (8), so it can be written as 8/9.

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Additional comment

The fraction 80/99 will be the 2-digit repeating decimal 0.808080...

The fraction 1111/1250 evaluates to 0.8888, a 4-digit decimal fraction that does not repeat.

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A fraction such as 0.142857...(6-digit repeat) can be written as ...

124857/999999 . . . . denominator has 6 nines

This fraction reduces to 1/7.

User Landry
by
3.2k points