Question

PLEASE HELP !!!!! I HAVE TO TURN THIS IN BY TOMORROW

Answer 1

Explanation:

Given the equation: y = 8 * 2ˣ, substitute the x-values in the table for x in your equation, to find the y-values.

For x = -1

`y = 8 * 2^x\\y=8*2^(-3)\\y=8*(1)/(2^3) < ==negative\ exponent\ property: x^(-n)=(1)/(x^n)\\y=8*(1)/(8)\\y=8*0.125\\y=1\\\\(-1,1)`

For -2:

`y = 8 * 2^x\\y=8*2^(-2)\\y=8*(1)/(2^2) < ==negative\ exponent\ property: x^(-n)=(1)/(x^n)\\y=8*(1)/(4)\\y=8*0.25\\y=2\\\\(-2,2)`

For -1:

`y = 8 * 2^x\\y=8*2^(-1)\\y=8*(1)/(2^1) < ==negative\ exponent\ property: x^(-n)=(1)/(x^n)\\y=8*(1)/(2)\\y=8*0.5\\y=4\\\\(-1,4)`

For 0:

`y = 8 * 2^x\\y=8*2^0\\y=8*(1)/(2^2) < ==zero\ exponent\ property: x^0=1\\y=8*1\\y=8\\\\(0,8)`

For 1:

`y = 8 * 2^x\\y=8*2^1\\y=8*2\\y=16\\\\(1,16)`

For 2:

`y = 8 * 2^x\\y=8*2^2\\y=8*4\\y=32\\\\(2,32)`

For 3:

`y = 8 * 2^x\\y=8*2^3\\y=8*8\\y=64\\\\(3,64)`

Hope this helps!