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The resistance, R, of a wire varies directly as its length

and inversely as the square of its diameter. If the
resistance of a wire 300 ft long with a diameter of
0.09 inches is 17113 ohms what is the resitance of
900 ft of the ame type of wire with a dister of
0.39 inches
Round off your final answer to the nearest hundredth.

User Aparpara
by
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2 Answers

5 votes


\qquad \qquad \textit{combined proportional variation} \\\\ \begin{array}{llll} \textit{\underline{y} varies directly with \underline{x}}\\ \textit{and inversely with }\underline{z^5} \end{array} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}x}{z^5}~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}


\begin{array}{llll} \textit{\tiny


\textit{when L = 900 ft and d = 0.39 in, what is

User Gumeo
by
4.9k points
11 votes

Answer:

2733.73

Explanation:


r = \frac{kl}{ {d}^(2) }


17113 = \frac{300k}{ {0.09}^(2) }


k = 0.462


r = \frac{0.462 * 900}{ {0.39}^(2) }


r = 2733.73

User RCB
by
4.9k points