Answer:
1. 10 bits
2. 1022 Hosts / Subnet
Step-by-step explanation:
Given Network ID is 172.20.0.0
Class B network contains :
Network ID = 16 bits
Host ID = 16 bits
For subnetting always host id bits are used.
Number of subnets required = 50. Subnets are always in power of two. Nearest power of two to 50 is 26 = 64.
So, to create subnet we require 6 bits from host id and 64 subnets can be created with those 6 bits.
1)
Number of host bits needed for new subnets for network information = 6 bits.
Therefore, New network information contains :
Network ID of subnet = 16 + 6 = 22 bits
Host ID = 16- 6 = 10 bits.
2)
Subnets required = 50
Subnets created with 6 bits = 64.
Number of subnets unused for future expansion = 64 - 50 = 14 subnets.
Host ID part contains 10 bits. Therefore, Total number of Hosts /Subnet = 210 = 1024 Hosts.
Number of usable hosts per subnet = 1024 -2 = 1022 Hosts / Subnet.