Answer:
d. 10.3 m
Step-by-step explanation:
For a nearsighted person,
1/f = (1/v)+(1/u).................... Equation 1
f = focal, v = image distance, u = object distance.
f = vu/(v+u)................. Equation 2
Given: v = -10 m, u = 300 m
Substitute into equation 2
f = (-10×300)/(-10+300)
f = -3000/290
f = -10.34 m
therefore a concave lens of focal length 10.34 m is required.
The right option is d. 10.3 m