Question

Write an equation of a line that passes through the point (−1,2) and is perpendicular to the line y=1/2x−3.

Answer 1

y = -2x

Explanation:

slope of line y=1/2x−3 m₁ = 1/2

perpendicular line slope m₂ = -2

line y = m₂x + b m₂: slope b: y intercept

pass (-1 , 2) b = y - m₂x = 2 - (-2) x (-1) = 0

perpendicular line equation: y = -2x