Question

An Arrow (0.5 kg) travels with velocity 60 m/s to the right when it pierces an apple (1 kg) which is initially at rest. After the collision, the arrow and the apple are stuck together. Assume that no external forces are present and therefore the momentum for the system is conserved. What is the final velocity (in m/s) of apple and arrow after the collision

Answer 1

Velocity after collision will be 20 m/sec

Step-by-step explanation:

We have given mass of arrow
`m_1=0.5kg`

Mass of arrow
`v_1=60m/sec`

Mass of apple
`m_2=1kg`

Apple is at rest so velocity of apple
`v_2=0m/sec`

According to conservation of momentum

Momentum before collision is equal to momentum after collision

`m_1v_1+m_2v_2=(m_1+m_2)v`

`0.5* 60+1* 0=(0.5+1)v`

`1.5v=30`

v = 20 m/sec