Answer:
6.941
Step-by-step explanation:
Step 1:
Representation.
Let Lithium−6 be isotope A
Let Lithium−7 be isotope B
Let the abundance of isotope A (Lithium-6) be A%
Let the abundance of isotope B (Lithium-6) be B%
Step 2:
Data obtained from the question. This includes:
Mass of isotope A (Lithium−6) =
6.01512
Abundance of isotope A (Lithium−6) = A% = 7.47%
Mass of isotope B (Lithium−7) = 7.016
Abundance of isotope B (Lithium−7) = B% = 92.53%
Atomic weight of lithium =?
Step 3:
Determination of the atomic weight of lithium. This is illustrated below:
Atomic weight = [(Mass of AxA%)/100] + [(Mass of BxB%)/100]
Atomic weight = [(6.01512x7.47)/100] + [(7.016x92.53)/100]
Atomic weight = 0.449 + 6.492
Atomic weight of lithium is 6.941