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Determine the number of Ni2+ ions involved in metalization (Ni plating) of an electrode for 30 sec in an electrolysis cell operated at 0.020A at 78 % current efficiency? The Faraday constant, F = 96485
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Determine the number of Ni2+ ions involved in metalization (Ni plating) of an electrode for 30 sec in an electrolysis cell operated at 0.020A at 78 % current efficiency? The Faraday constant, F = 96485 C/mol and Avogadro # NA = 6.023×1023. What will be the number of Ag+ ions if Ag is plated under the same experimental conditions instead of Ni2+?

User Vinu M Shankar
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Answer: The number of Ni2+ ions is 1.46 × 10^18 ions

The number of Ag+ ions is 2.92 × 10^18 ions

Explanation: Please see the attachments below

Determine the number of Ni2+ ions involved in metalization (Ni plating) of an electrode-example-1
Determine the number of Ni2+ ions involved in metalization (Ni plating) of an electrode-example-2
Determine the number of Ni2+ ions involved in metalization (Ni plating) of an electrode-example-3
User Bradenm
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