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An accident happens in the lab of Professor Utonium, and a radioactive element X is released in the form of a gas at around 4:00 am. Element X has a short half-life (25 min), and the lab would be considered safe when the concentration of X drops by a factor of 10. Considering the decomposition of element X is of first-order, what is the earliest time Professor Utonium can come back to do experiments in the lab

User Puerto
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Answer:

5:22 am

Step-by-step explanation:

The gas X decays following a first-order reaction.

The half-life (
t_(1/2)) is 25 min. We can find the rate constant (k) using the following expression.


k = (ln2)/(t_(1/2)) =(ln2)/(25min) = 0.028 min^(-1)

We can find the concentration of X at a certain time (
[X]) using the following expression.


[X] = [X]_0 * e^(-k * t)

where,


[X]_0: initial concentration of X

t: time elapsed


([X])/([X]_0)= e^(-k * t)\\(1/10[X]_0)/([X]_0)= e^{-0.028min^(-1) * t}\\t=82min

The earliest time Professor Utonium can come back to do experiments in the lab is:

4:00 + 82 = 5:22 am

User Anamarie
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