Question

in the adjoining figure P A and PB are tangents from P to a circle with Centre O if angle APB is equal to 40 degree then find angle ACB​

Answer 1

Explanation:

40° + 90° + 90° + angle ACB = 360°

220° + angle ACB = 360°

angle ACB = 360° - 220°

Therefore angle ACB = 140°

Hope it will help :)