Answer:
(0.339, 0.391)
Explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{(\pi(1-\pi))/(n)}](https://img.qammunity.org/2021/formulas/mathematics/college/fmbc52n1wcsstokpszqrr2jempwxl2no1b.png)
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
![n = 1295, \pi = (473)/(1295) = 0.365](https://img.qammunity.org/2021/formulas/mathematics/college/k0le7t8n5cmxy7rdweom96uzf60773v7hf.png)
95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{(\pi(1-\pi))/(n)} = 0.365 - 1.96\sqrt{(0.365*0.635)/(1295)} = 0.339](https://img.qammunity.org/2021/formulas/mathematics/college/pydzxmoff8koz9l2sp0afz556rzlw4mqkr.png)
The upper limit of this interval is:
![\pi + z\sqrt{(\pi(1-\pi))/(n)} = 0.365 + 1.96\sqrt{(0.365*0.635)/(1295)} = 0.391](https://img.qammunity.org/2021/formulas/mathematics/college/qq5d3yuvkc4snimxjmwi3wy3ykgiv86z86.png)
So the correct answer is:
(0.339, 0.391)