Answer:
![AB=19.8\ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/vxfgenz2a49jn4ln7cg6dth2r9uh7j4g54.png)
Explanation:
step 1
Find the measure of angle A
we know that
Triangle ABC is a right triangle
so
The sum of angle A plus angle B must be equal to 90 degrees by complementary angles
----> equation A
![(B)/(A)=(3)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/bho5u75pxtpza4tj18qyocyp8i2z0czlt4.png)
so
----> equation B
substitute equation B in equation A
![A+1.5A=90](https://img.qammunity.org/2021/formulas/mathematics/high-school/gt3bo4e4oj5uxael3tp48if6rislw5nk84.png)
solve for A
![2.5A=90\\A=36^o](https://img.qammunity.org/2021/formulas/mathematics/high-school/by0fmo7p0258kxnwre9eu56e85389rkejv.png)
step 2
Find the length of side AB (hypotenuse)
we know that
----> by CAH (adjacent side divided by the hypotenuse)
substitute the given values
![cos(36^o)=(16)/(AB)](https://img.qammunity.org/2021/formulas/mathematics/high-school/926mmi417skxg9lz43y7x7ka46vea3o6in.png)
![AB=(16)/(cos(36^o))=19.8\ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/jmz4xsyphknykgjof3wjsmx233bmwson9t.png)