80.3k views
5 votes
I don’t know how to solve this. Can anyone help me get the answer and the work

I don’t know how to solve this. Can anyone help me get the answer and the work-example-1
User Carollyn
by
7.7k points

2 Answers

4 votes

Answer:

{ -
(2)/(3), 12 }

Explanation:

We can solve the equation by factoring it

3x² - 34x - 24 = 0

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 3 × - 24 = - 72 and sum = - 34

The factors are - 36 and + 2

Use these factors to split the x- term

3x² - 36x + 2x - 24 = 0 ( factor the first/second and third/fourth terms )

3x(x - 12) + 2(x - 12) = 0 ← factor out (x - 12) from each term

(x - 12)(3x + 2) = 0

Equate each factor to zero and solve for x

x - 12 = 0 ⇒ x = 12

3x + 2 = 0 ⇒ 3x = - 2 ⇒ x = -
(2)/(3)

Thus the solution set is { -
(2)/(3), 12 }

User Granaker
by
8.9k points
4 votes

If you have to check whether a number is a solution of a given equation, just plug that number in the equation and see if you get something true or false.

For example, the first option claims that -2 and 6 are solutions to the equation.

Let's check it! If we substitute
x=-2 in the equation we get


3(-2)^2-34(-2)-24 = 12+68-24=56 \\eq 0

So, -2 isn't a solution to this equation. Let's check 6:


3(6)^2-34(6)-24 = 108-204-24=-120 \\eq 0

So, 6 isn't a solution either.

Keep going like this and you'll find the correct set of solutions.

User JoshFinnie
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories