Question

In ABC, AD is the angle bisector of /_BAC.

What is BD?
Enter your answer as a decimal,
? in.​

Answer 1

It’s 1.8 also Subscribe to XBooDeadInsideX -_- on yt

Answer 2

1.8

Explanation:

ADC is a right angled triangle. So is ADB.

For right angled triangle ADC,

`{ad}^(2) + {dc}^(2) = {ac}^(2) \\ {x}^(2) + {3}^(2) = {4}^(2) \\ {x}^(2) + 9 = 16 \\ {x}^(2) = 16 - 9 = 7 \\ x = √(7)`

For right angled triangle ADB,

`{ad}^(2) + {db}^(2) = {ab}^(2) \\ 7 + {y}^(2) = {3.2}^(2) \\ 7 + {y}^(2) = 10.24 \\ {y}^(2) = 10.24 - 7 \\ {y}^(2) = 3.24 \\ y = √(3.24) \\ y = 1.8`