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O urna contine bile numerotate de la 1 la 27. Se extrage la intamplare o bila; se considera castigator Mihai, daca iese o bila numerotata cu un numar prim , respectiv Andrei daca iese o bila numerotata cu un patrat sau cub perfect. Care din cei doi copii are sanse mai mari de a castiga ?

User IT Goldman
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1 Answer

6 votes

Answer:

Mihai

Explanation:

  • Numere prime de la 1 la 27

2, 3, 5, 7, 11, 13, 17, 19, 23

avem 9 numere prime

P(Mihai) = 9×100/27 = 900/27 = 33,(3) %

  • Patrate perfecte de la 1 la 27

1, 4, 9, 16, 25

Cuburi perfecte de la 1 la 27

1, 8, 27

avem 7 numere patrate si cuburi perfecte (1 se repeta)

P(Andrei) = 7×100/27 = 700/27 = 25,92 %

Observam ca Mihai are probabilitatea mai mare deci el este castigatorul

User Vasiliy Galkin
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