Question

How any moles of H2O will be produced from 12.3 moles of HCL reacting with Ca(OH)2?

Answer 1

\large \boxed{\text{12.3 mol HCl}}

Step-by-step explanation:

We need a balanced chemical equation with moles.

2HCl +Ca(OH)₂ ⟶ CaCl₂ + 2H₂O

n/mol: 12.3

The molar ratio is 2 mol H₂O:2 mol HCl.

`\text{Moles of H$_(2)$O} = \text{12.3 mol HCl} * \frac{\text{2 mol H$_(2)$O}}{\text{2 mol HCl}} = \textbf{12.3 mol HCl}\\\\\text{The reaction produces $\large \boxed{\textbf{12.3 mol HCl}}$}`