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A force of 20 N acts upon 5 kg block caculate the accerleration of the object

1 Answer

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Answer:


\boxed{\text{4 m $\cdot$ s$^(-2)$}}

Step-by-step explanation:

F = ma


a = (F)/(m) = \frac{\text{20 N}}{\text{5 kg}} * \frac{\text{1 kg$\cdot$ m $\cdot$ s$^(-2)$}}{\text{1 N}} = \text{4 m $\cdot$ s$^(-2)$}\\\\\text{The acceleration of the object is } \boxed{\textbf{4 m $\cdot$ s$^{\mathbf{-2}}$}}

User Modesto
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