Question

A bag contains 8 red crayons, 14 purple crayons, 6 yellow crayons, and 4 green crayons. A crayon is selected, replaced, and then another is selected. Find the probability: P (yellow and red) .

Answer 1

P(yellow the red) =
`(3)/(32)`

Explanation:

P(yellow and red) = P(yellow then red) + P(red then yellow)

P(yellow then red) =
`(6)/(32) . (8)/(32) = (3)/(64)`

P(red then yellow) = P(yellow then red)

P(yellow and red) =
`(3)/(64) + (3)/(64) = (3)/(32)`