Question

A circular bar will be subjected to an axial force (P) of 2000 lbf. The bar will be made of material that has a strength (S) of 24 kpsi. After some calculation, the designer has selected a standard 1/2 in diameter (d) bar. The factor of safety (n) is ____. Round the answers to three significant digits.

Answer 1

`n = 2.36`

Step-by-step explanation:

The stress experimented by the circular bar is:

`\sigma = \left[(2000\, lbf)/((\pi)/(4)\cdot (0.5\,in)^(2))\right]\cdot \left((1\,kpsi)/(1000\,psi) \right)`

`\sigma = 10.186\,kpsi`

The safety factor is:

`n = (24\,kpsi)/(10.186\,kpsi)`

`n = 2.36`