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there are 3 numbers in ascending order such that the difference of first two is 10 and that of last two is 12. if the sum of three numbers is 47, find the least number.​

User KenobiBastila
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2 Answers

22 votes
22 votes

Answer:

5

Explanation:

there are 3 numbers in ascending order such that the difference of first two is 10 and-example-1
User Whitlaaa
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3.1k points
22 votes
22 votes

Answer:

17/3

Explanation:

x + y + z = 47

y - x = 10 x = y - 10

z - y = 10 z = 10 + y

y-10 + y + 10 + y = 47

3 y = 47

y = 47/3 x = 17/3 z = 77/3

User Samuel James
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3.3k points