The question is incomplete, the correct question is:
Charles needs to fill a large fish tank with water using a hose. he has two hoses from which to choose. Water flows through each hose at a constant rate. The graph below shows the amount of water, in gallons , that flows through holes A based on the number of minutes used. A total of 110 gallo s of water can flow through Hose B in 10 minutes. Which hose has a faster water rate, in gallons per minute, and what is that rate?
Answer:
Hose B has a faster water flow rate in comparison to Hose A
Explanation:
For Hose B,
From the information above, it is said that a total of 110 gallons of water can flow through hose b in 10 minutes. Therefore, divide 110 by 10 to get the amount of water that flows through hose b in gallons in one minute.
So,
110/10=11
y=11 x
This implies that 11 gallons of water flows through hose b in 1 minute.
For Hose A,
Select two points to get the rate of change,and then subtraction of y2 from y1 and x2 from x1 is done
Points selected: (2,12) , (4,24)
(x1,y1)=(2,12)
(x2,y2)=(4,24)
So, Subtract 24 from 12 and 2 from 4
M=y2-y1/x2-x1= 24-12 / 2-4= 12/2=6
This implies that in hose a a total of 6 gallons of water flows in one minute.
Therefore, the equation for hose a is y=6 x
In conclusion, hose b has a faster water flow rate since y=6 x < y=11 x.