Answer:
4.2 L O₂ is needed to completely react with 2.8 L hydrogen sulfied.
Step-by-step explanation:
Without pressure and temperature we cannot calculate the this vale
We assume that the reaction take place under standard Temperature and Pressure(STP).
At STP, One mole (
particles) of any gas occupied volume 22.4 L.
The balanced equation of this reaction is
![2H_2S+3O_2\rightarrow 2SO_2+2H_2O](https://img.qammunity.org/2021/formulas/chemistry/high-school/hjex7gpqeawzd36f896un95i278fudbju7.png)
Now we use molar ratio.
![2.8L\ H_2S . \ (1 mol\ H_2S)/(22.4L \ H_2S)\ . \ (3 mol\ O_2)/(2 mol \ H_2S) \ . \ (22.4L\ O_2)/(1 mol\ O_2)](https://img.qammunity.org/2021/formulas/chemistry/high-school/phfvxvtyiev4b6dae60crwmqc73j5qcwq3.png)
=4.2 L O₂
4.2 L O₂ is needed to completely react with 2.8 L hydrogen sulfied.