Question

Ben is filling his cylinder shaped pool up to 80% of its capacity. If his pool is 6 feet deep and has a diameter of 18 feet, how much water will he put in the pool?

Answer 1

34601 liters

Explanation:

Given:

Ben is filling his cylinder shaped pool up to 80% of its capacity.

His pool is 6 feet deep and has a diameter of 18 feet.

Question asked:

How much water will he put in the pool?

Solution:

First of all we will find volume of cylinder:

Diameter = 18 feet

Radius, r =
`(Diameter)/(2) =(18)/(2) =9\ feet`

Height, h = 6 feet

As we know:

`Volume\ of \ cylinder=\pi r^(2) h`

`=(22)/(7) *(9)^(2) * 6\\ \\=(22)/(7) *81 * 6\\ \\ =(10692)/(7) \\ \\ =1527.42\ cubic\ feet`

Now, as given that pool is being filled up to 80%, we have to find quantity of water he will put in the pool:-

Quantity of water filled = 80% of the volume of the pool

`=(80)/(100) *1527.42\\ \\ =1221.93\ cubic feet`

Now, convert it into liters.

1 cubic feet = 28.31 liters

1221.93 cubic feet = 28.31
`*` 1221.93 = 34,601.20 liters

Therefore, he will put about 34601 liters water in the pool.