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A gas occupies 3.5 L at standard pressure. Find the volume of the gas when the pressure is 1.5 atm. (Remember, standard pressure equals 101.3kPa, 1atm, or 760mmHg.)

User Saiwing
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2 Answers

4 votes

Answer:


V_2=2.3L

Step-by-step explanation:

Hello,

In this case, we use the Boyle's law which allows us to analyze the volume-pressure behavior as an inversely proportional relationship:


p_1V_1=p_2V_2

Thus, solving for the resulting volume,
V_2, we obtain:


V_2=(p_1V_1)/(p_2)=(1atm*3.5L)/(1.5atm)\\ \\V_2=2.3L

Best regards.

User Ziarek
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3.8k points
7 votes

Answer:

2.33 L

Step-by-step explanation:

Boyle's Law explains that at constant temperature, the pressure of an ideal gas is inversely proportional to its volume.

P ∝ (1/V)

P = (k/V)

k = constant of proportionality

k = PV

k = k

P₁V₁ = P₂V₂ = k

The gas occupies 3.5 L at standard pressure. Find the volume of the gas when the pressure is 1.5 atm. Standard pressure equals 1atm.

From Boyle's law

P₁V₁ = P₂V₂

P₁ = 1 atm

V₁ = 3.5 L

P₂ = 1.5 atm

V₂ = ?

1 × 3.5 = 1.5 × V₂

V₂ = 2.333 L

Hope this Helps!!

User Mozillazg
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3.3k points