Question

(a) In Coulomb scattering of 7.50-MeV protons by a target of 'Li, what is the energy of the elastically scattered protons at 90°? (b) What is the energy of the inelastically scattered protons at 90° when the 'Li is left in its first excited state (0.477 MeV)?

Answer 1

First the charge is given 7.50×10^-6

Step-by-step explanation:

so that we have

`90`

• so that their is no cross sectional area of this angle

then the direction is one is left and other one is right so thats my hint