Question

Two vectors have magnitudes of 1.8 m and 2.4 m. How are these vectors arranged, so their sum is 0.6 m?

Answer 1

Perpendicular

Step-by-step explanation:

write the angle between them as a

cosine theoreme

`0.6^(2) =1.8^(2) +2.4^(2)-2*1.8*2.4*cos(a)`

cos(a)=(3.24+5.76-0.6)/(2*1.8*2.4)

cos(a)=1

a=90°