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Express secA in terms of tanA​

User Luddek
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1 Answer

6 votes

Answer:


{ \sec} A = \sqrt{1 + { \tan}^(2) A }

Explanation:


{ \sec}^(2) A = 1 + { \tan}^(2) A \\ \\ \implies \: { \sec} A = \sqrt{1 + { \tan}^(2) A }

User Ralf Kleberhoff
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